Solution
Given Forces can be shown below
F1=50NF2=50NF_1=50N\\F_2=50N\\F1=50NF2=50N
Firstly we have to find components in
F3x=F3cos30°=60.62NF3y=F3sin30°=35NF_{3_x}=F_3\cos30^°=60.62N\\F_{3_y}=F_3\sin30^°=35NF3x=F3cos30°=60.62NF3y=F3sin30°=35N
Now in resultant forces are found in -x and +y axis as shown below

Finally resultant force of all three forces is given by
FR=152+(10.62)2F_R=\sqrt{15^2+(10.62) ^2}FR=152+(10.62)2 =337.8N
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