Question #138703

The coordinate of a particle in meters is given by x(t)=2.0t-2.0t², where the time t is in seconds. The particle is momentarily at rest at time t equal to?

Expert's answer

If the particle is at rest, then its velocity is zero, so we find the velocity equation, which is equal to the derivative of the coordinate equation v(t)=(x(t))=24×tv(t)=(x(t))^{\prime}=2-4\times t , for v=0v=0 it will be

0=24×t0=2-4\times t

t=0.5t=0.5 s.


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