Answer to Question #138703 in Mechanics | Relativity for am

Question

The coordinate of a particle in meters is given by x(t)=2.0t-2.0t², where the time t is in seconds. The particle is momentarily at rest at time t equal to?

Answer 1

If the particle is at rest, then its velocity is zero, so we find the velocity equation, which is equal to the derivative of the coordinate equation $v(t)=(x(t))^{\prime}=2-4\times t$ , for $v=0$ it will be

$0=2-4\times t$

$t=0.5$ s.