Answer to Question #138703 in Mechanics | Relativity for am

Question #138703
The coordinate of a particle in meters is given by x(t)=2.0t-2.0t², where the time t is in seconds. The particle is momentarily at rest at time t equal to?
1
Expert's answer
2020-10-16T10:57:55-0400

If the particle is at rest, then its velocity is zero, so we find the velocity equation, which is equal to the derivative of the coordinate equation v(t)=(x(t))=24×tv(t)=(x(t))^{\prime}=2-4\times t , for v=0v=0 it will be

0=24×t0=2-4\times t

t=0.5t=0.5 s.


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