Question

A person walks 25.00 north of east for 3.10 km. How far would she have to walk due north and due east to arrive at the same location?

Answer 1

let the distance due east = $x$

$Cos25^{o}= \frac{x}{3.1}$

$x=3.1 \times Cos25^{o}= 2.81 Km$

let the distance due north $=y$

$Sin25^{o} = \frac{y}{3.1}$

$y= 3.1 \times Sin25^{o} = 1.31 Km$