Solution
Friction force is given by
F=μN=μmgF=\mu N=\mu mgF=μN=μmg
where N is normal force.
Using energy conservation
Fd=ΔKE=mv22Fd=\Delta KE=\frac{mv^2}{2}Fd=ΔKE=2mv2
d=mv22F=mv22μmgd=\frac{mv^2}{2F}=\frac{mv^2}{2\mu mg}d=2Fmv2=2μmgmv2
d=v22μgd=\frac{v^2}{2\mu g}d=2μgv2
This equation clearly shows that distance d does not depend on mass.
Therefore d remains same.
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