Case-1
From principle of conservation of linear momentum we get
4×100+16×40=20vf
vf=52m/s
Ki=1/2(4×1002+16×402)
Ki=32800J
Kf=(1/2)×20×522
Kf=27040J
Energy loss is
Ki−Kf=5760J
Case-2
From principle of conservation of linear momentum we get
16×40−6×100=20vf
vf=12m/s
Kf=1440J
Energy loss is
Ki−Kf=31360J
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