Answer to Question #136613 in Mechanics | Relativity for mungaster

Question

A ball is hit so that it travels straight upward after being struck by the bat. A fan observes that it takes 3.00 s for the ball to reach its maximum height. Find (a) the ball’s initial velocity and (b) the height it reaches.

Answer 1

solution

given data

time taken to achieve maximum height(t)=3 sec

by the first equation of motion

$v=u+gt$

at maximum height v=0 m/s

g= - 9.8 m/s^2

putt the value

$u=9.8\times 3\\u=29.4m/s$

by the second equation of motion

$H_{max}=ut+\frac{1}{2}gt^2$

$H_{max}=29.4\times3-\frac{1}{2}\times 9.8\times3^2\\=44.1m$

so initial velocity is 29.4 m/s and maximum height is 44.1 m .