solution
given data
height of wall (H)=100 m
time taken by the child to reach the lower point of wall
"H=ut+\\frac{1}{2}gt^2"
u=o m/sec
so
"t=\\sqrt{\\frac{2H}{g}}\\\\value\\quad of\\space g=10m\/s\\\\t=4.47s"
after 1 sec superman saw him so he has t2 =4.47 - 1=3.47 s to save the child
speed of superman (v)
"v=\\frac{H}{t}=\\frac{100}{3.47}\\\\=28.82 m\/sec"
so speed of superman should be 28.82 m/s.
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