Answer to Question #136401 in Mechanics | Relativity for Sneha

Question

What is maximum height expression for projectile motion.

Answer 1

The maximum height for projectile motion:

$h_{max}=\frac{v_0^2sin^2\alpha}{2g}$

where $v_0$ - the initial velocity,

$\alpha$ - the angle at which the projectile is moved above the horizon.

$g=10\frac{m}{s^2}$