Answer to Question #136360 in Mechanics | Relativity for Sridhar

Question #136360

A force required just to prevent a body sliding down a rough inclined plane of angle  45° and cocfficient of friction 0.6 is F. The minimum force required to move the  body up the plane is

Ans 4F


1
Expert's answer
2020-10-05T16:20:57-0400
F=μmgcos45+mgsin45mg=Fμcos45+sin45Fup=μmgcos45+mgsin45Fup=(μcos45+sin45)Fμcos45+sin45Fup=(0.6cos45+sin45)F0.6cos45+sin45Fup=4FF=-\mu mg \cos{45}+mg\sin{45}\\mg=\frac{F}{-\mu \cos{45}+\sin{45}}\\F_{up}=\mu mg \cos{45}+mg\sin{45}\\\\F_{up}=(\mu \cos{45}+\sin{45})\frac{F}{-\mu \cos{45}+\sin{45}}\\F_{up}=(0.6 \cos{45}+\sin{45})\frac{F}{-0.6 \cos{45}+\sin{45}}\\\\F_{up}=4F


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment