Question

A person walks 25.00 north of east for 3.10 km. How far would she have to walk due north and due east to arrive at the same location?

Answer 1

Let's draw a drawing for the task

Where

$OB=3.10km$

Then

a person will cover the distance to the north

$OA=OB \cdot \sin(25^0)=3.1 \cdot 0.423=1.31 km$

a man will walk the distance to the east

$AB=OB \cdot \cos(25^0)=3.1 \cdot 0.906=2.81 km$