A ball is thrown upward from the ground with an initial speed of 25 m/s; at the same instant, another ball is dropped from a building 15 m high. After how long will the balls be at the same height above the ground?
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Expert's answer
2020-10-13T09:32:18-0400
Y1=(1/2)gt2
Y2=25t−(1/2)gt2
Y1+Y2=15
Solving the above three equations we get t= 0.6 second
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