m1ax=m2gx−m1gx;ax=m2gx−m1gxm1;ax=(m2−m1)×gxm1=(150−100)×9.8100=4.9ms2;ANSWER:the acceleration of the body is4.9ms2m_1a_x=m_2g_x-m_1g_x ;a_x=\frac{m_2g_x-m_1g_x}{m_1};\\a_x=\frac{(m_2-m_1)\times g_x}{m_1}=\frac{(150-100)\times 9.8}{100}=4.9\frac{m}{s^2};\\ANSWER:the\ acceleration\ of \;the\;body\;is\\4.9\frac{m}{s^2}m1ax=m2gx−m1gx;ax=m1m2gx−m1gx;ax=m1(m2−m1)×gx=100(150−100)×9.8=4.9s2m;ANSWER:the acceleration ofthebodyis4.9s2m
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