Question

A force of 10N is angle 30degree from x-axis. Find out it's magnitude y -axis direction.

Answer 1

$\tan \theta ={x \over y}$

where $\theta$ is angle between the force and the x-axis

$\tan 30=10/y$

y=17.321N

direction is given by;

$\tan ^{-1} =y/x$

$\theta =\tan ^{-1}\dfrac{17.321}{10}$

=60.00070462

=$60\degree$