The amount of substance (measured in moles) is
ν=mμ\displaystyle \nu = \frac{m}{\mu}ν=μm
where μ(H2O)=2⋅Ar(H)+Ar(O)=2⋅1+16=18\mu (H_2O) = 2\cdot A_r(H)+ A_r(O) = 2 \cdot 1 +16 = 18μ(H2O)=2⋅Ar(H)+Ar(O)=2⋅1+16=18 g/mol.
Mass can be found from
m=ρ⋅V=ρ⋅πr2h=1⋅3.1415⋅5.662⋅15.8=1590m = \rho \cdot V = \rho \cdot \pi r^2 h = 1 \cdot 3.1415 \cdot 5.66^2 \cdot15.8 = 1590m=ρ⋅V=ρ⋅πr2h=1⋅3.1415⋅5.662⋅15.8=1590 g
So,
ν=1590 g18 g/mol=88.3 mol.\nu = \frac{1590 \;g}{18 \; g/mol}= 88.3 \; mol.ν=18g/mol1590g=88.3mol.
Answer: 88.3 mol
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