Let SSS is total distance, then S=2πr⋅12≈2⋅3,14⋅5⋅12≈377mS=2\pi r\sdot12\approx2\sdot3,14\sdot5\sdot12\approx377mS=2πr⋅12≈2⋅3,14⋅5⋅12≈377m
Let ddd is displacement, then d=0d=0d=0