Answer to Question #13432 in Mechanics | Relativity for harisha

Question

A block of mass 2*1000g moving at 2*100m/s collides with another block of same mass at rest. if actual loss of K.E. is half of the maximum then the coefficient of restitution is

Answer 1

KE1max = m * V^2 / 2 = 2 * 200^2 / 2 = 40000 J
Loss is KE1 = KE2 = KE1max / 2
= 20000 J.
So, after the impact V1 = V2.
The coefficient of restitution is
given by
C = (Vb - Va) / (Ua - Ub)
for two colliding objects, where
Va
is the final velocity of the first object after impact
Vb is the final
velocity of the second object after impact
Ua is the initial velocity of the
first object before impact
Ub is the initial velocity of the second object
before impact
C = (V2 - V1) / (200 - 0) = 0