Answer to Question #134000 in Mechanics | Relativity for sridhar

Question #134000
a ball is dropped from a height h from rest.the ball travels (h/2) in last 1.0s the total time taken to the ball hit the ground is...
Ans 3.41s
1
Expert's answer
2020-09-22T15:36:32-0400

tt0=12hg2h/2g=1t-t_0=1\to \sqrt{\frac{2h}{g}}-\sqrt{\frac{2h/2}{g}}=1\to


h(2g1g)=1\sqrt h(\sqrt{\frac{2}{g}}-\sqrt{\frac{1}{g}})=1\to


h=1(2g1g)2=57.197(m)h=\frac{1}{(\sqrt{\frac{2}{g}}-\sqrt{\frac{1}{g}})^2}=57.197(m)


t=2hg=257.1979.81=3.41(s)t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2\cdot 57.197}{9.81}}=3.41(s)


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