Question

A plant pot of mass 3 kg falls from a balcony and drops 10.5 m to the ground. It falls freely under gravity. Find the speed of the plant pot just before it hits the ground.

Thanks

Answer 1

According to the law of the conservation of energy:

$mgh=\frac{mv^2}{2}$

$gh=\frac{v^2}{2}$

$v^2=2gh$

$v=\sqrt{2gh}$

$v=\sqrt{2*10*10.5}=\sqrt{210}=14.5(\frac{m}{s})$