Consider a system of three equal mass particles moving in aplane;their positions are given by aiiunit vector+bij unit vector
For particle 1,a1=3t^2+4 b1=0
For particle 2,a2=7t+5 b2=2
For particle 3,a3=2t b3=3t+4
Determine the position and velocity of the centre of mass as functions of time
1
Expert's answer
2012-08-21T10:57:09-0400
The position& of the center of mass:
ac = (a1+a2+a3)/3 = (3t²+4+7t+5+2t)/3 = (3t²+9t+9)/3 = t²+3t+3 bc = (b1+b2+b3)/3 = (0+2+3t+4)/3 = t+2
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