Question #133695

A certain liquid has a unit weight of 57 KN/m^3. Compute the mass density in kg/m^3.

Expert's answer

A unit weight is

γ=PV=57103  Nm3\displaystyle \gamma =\frac{P}{V} =57 \cdot 10^3\; \frac{N}{m^3}

By definition, weight P=mgm=PgP = mg \Rightarrow m = \displaystyle \frac{P}{g}

Mass density is

ρ=mV=PgV=PV1g=γg=571039.81=5.81103  kgm3\displaystyle \rho = \frac{m}{V} = \frac{P}{gV} = \frac{P}{V} \cdot \frac{1}{g} = \frac{\gamma}{g} = \frac{57 \cdot 10^3}{9.81} = 5.81 \cdot 10^3 \; \frac{kg}{m^3}

Answer: 5.81103  kgm35.81 \cdot 10^3 \; \frac{kg}{m^3}.

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