Question #133230

During a particular thunderstorm, the electric potential between a cloud and the ground is Vcloud - Vground = 1.1 x 10^8 V, with the cloud being at the higher potential. What is the change in an electron's potential energy when the electron moves from the ground to the cloud?

Expert's answer

solution

potential difference (ΔV)=1.1×108V(\Delta V)=1.1\times10^{8}V

charge of electron(q)=1.6×1019C-1.6\times10^{-19}C


relation between electric potential and electric potential energy is given by


ΔU=qΔV=(1.6×1019)(1.1×108)\Delta U=q\Delta V=(-1.6\times10^{-19})(1.1\times10^8)


ΔU=1.67×1011J\Delta U=-1.67\times10^{-11}J


therefore change in electrostatic potential energy is 1.67×1011J.-1.67\times10^{-11}J.



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