Question #133230
During a particular thunderstorm, the electric potential between a cloud and the ground is Vcloud - Vground = 1.1 x 10^8 V, with the cloud being at the higher potential. What is the change in an electron's potential energy when the electron moves from the ground to the cloud?
1
Expert's answer
2020-09-15T10:03:53-0400

solution

potential difference (ΔV)=1.1×108V(\Delta V)=1.1\times10^{8}V

charge of electron(q)=1.6×1019C-1.6\times10^{-19}C


relation between electric potential and electric potential energy is given by


ΔU=qΔV=(1.6×1019)(1.1×108)\Delta U=q\Delta V=(-1.6\times10^{-19})(1.1\times10^8)


ΔU=1.67×1011J\Delta U=-1.67\times10^{-11}J


therefore change in electrostatic potential energy is 1.67×1011J.-1.67\times10^{-11}J.



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