Question

Carbon tetrachloride with a mass of 1000kg is placed in container with 0.350 m³ in volume. Calculate specific weight.

Answer 1

The specific weight of carbon tetra-chloride ($\Large CCI\scriptscriptstyle 4$ ) is its weight per unit volume.

Mass of $\Large CCI\scriptscriptstyle 4$ (m)=1000 kg

volume of $\Large CCI\scriptscriptstyle 4$ (v) =$0.350m^{3}$ =350 litres.

The weight of $\Large CCI\scriptscriptstyle 4$ =m*g

=1000*9.81 =$9810N$

Changing to kilonewtons (kN) =${9810 \scriptscriptstyle N\over1000\scriptscriptstyle N}*1kN$

w=9.81KN

specific weight = $\frac w V$

=${9.810 \scriptscriptstyle KN\over 0.350\scriptscriptstyle m^3}$

=28.0286 kg/m³