Question #132827

a particle of mass 4m explode in air in four equal masses with velocity v making angle 90 degree to each other then find its kinetic energy.

Expert's answer

Since equal masses are exploding in 90 degrees with each other so the momentum will be zero here.

let's calculate kinetic energy for each

KE =12mv2\frac12mv^2

similarly we have three more masses of mass m

total KE = 4×12×mv2=2mv24\times\frac12\times mv^2=2mv^2


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