Answer to Question #132406 in Mechanics | Relativity for Jessica

Question #132406
A 4.8 μC point charge is placed in an external uniform electric field that has a magnitude of 72000 N/C. At what distance from the charge is the net electric field zero?
1
Expert's answer
2020-09-17T08:24:31-0400

The electric field due to charge q is given by

E=kqr2E = \frac{k|q|}{r^2}

The distance when the electric field is zero is given by

E1=E2E_1 = E_2

E1=kqr2E_1 = \frac{kq}{r^2}

72000  N/C=(9×109)(4.8×106C)r272000\; N/C= \frac{(9 \times 10^9)(4.8\times 10^{-6}C)}{r^2}

r2=6r^2 = 6

r=6=2.45  mr =\sqrt6=2.45\; m

Answer: 2.45 m

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