Question

The electric potential energy stored in the capacitor of a defibrillator is 100 J, and the capacitance is 170 μF. What is the potential difference across the capacitor plates?

Answer 1

$W=\frac{CU^2}{2}\to U=\sqrt\frac{2W}{C}=\sqrt\frac{2\cdot 100}{170\cdot10^{-6}}\approx1085(V)$