As Lorenz transformation is u=(u′2+v2+2vu′cosθ′−(vu′sinθ′c)21+vu′cosθ′c2u=\frac{\sqrt{(u'^2+v^2+2vu'\cos\theta'-(\frac{vu'\sin\theta'}{c})^2}}{1+\frac{vu'\cos\theta'}{c^2}}u=1+c2vu′cosθ′(u′2+v2+2vu′cosθ′−(cvu′sinθ′)2 (J.D.Jackson,Classical Electrodynamics, N.Y-London,1962)
We have u′=v=c/2,θ′=π/2u'=v=c/2, \theta'=\pi/2u′=v=c/2,θ′=π/2 then u=c7/16u=c\sqrt{7/16}u=c7/16
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