Question #132290

find the path of center of mass and center of mass velocity if a chain of length L is moving on a circular path of radius R with velocity v.and L=pi R.

Expert's answer

Explanations & Calculations




  • Consider the figure to get a better understanding.
  • Distance to the com (ox) of an arc of radius r is given by, ox=rsinαα\small ox = \large \frac{r \sin \alpha}{\alpha}
  • Since L=πR\small L= \pi R, the chain makes a semicircular arc whose com lies at a distance from the origin as ox=Rsinπ2π2=2Rπ\small ox = \large \frac{R \sin \frac{\pi}{2}}{\frac{\pi}{2}} = \frac{2R}{\pi}


  • Therefore, as the chain rotates, its center of mass also changes it position being fixed at x which describes a circular path of radius ox.


  • Since the chain moves on a circular path at a constant speed, it has an (constant) angular velocity ω\small \omega, which is a constant value about the axis for a given circular motion .
  • Therefore,

ω=VR=V1oxVR=V12RπV1=2Vπ\qquad\qquad \begin{aligned} \small \omega &= \small \frac{V}{R}= \frac{V_1}{\text{ox}}\\ \small \frac{V}{R}&= \small \frac{V_1}{\frac{2R}{\pi}}\\ \small V_1 &= \small \frac{2V}{\pi} \end{aligned}


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