Maximum height will be achieved when, velocity inside the hose is low i.e "V_1=0" , at the top of the water trajectory "V_2=0" and the reference level "z_1=0"
Bernoulli's equation
"\\frac{P_1}{\\rho g}+\\frac{V^2_1}{2g}+z_i=\\frac{P_2}{\\rho g}+\\frac{V^2_2}{2g}+z_2"
Since
"\\frac{V^2_1}{2g}=\\frac{V^2_2}{2g}=0"
the equation reduces to
"\\frac{P_1}{\\rho g}=\\frac{P_{atm}}{\\rho g}+z_2"
Solving for "z_2" and substituting.
"z_2=\\frac{P_1-P{atm}}{\\rho g}=\\frac{P_1,{gauge}}{\\rho g}"
"\\frac{400kPa}{1000kg\/m^3\\times9081m\/s^2}(\\frac{1000N\/m^2}{1kPa})(\\frac{1kg.m\/s^2}{1N})"
answer ="40.8m"
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