Question #130124
Water is flowing from a garden hose (Fig. below). A child places his thumb
to cover most of the hose outlet, causing a thin jet of high-speed water to
emerge. The pressure in the hose just upstream of his thumb is 400 kPa. If
the hose is held upward, what is the
maximum height that the jet could achieve?
1
Expert's answer
2020-09-01T11:01:24-0400

Maximum height will be achieved when, velocity inside the hose is low i.e V1=0V_1=0 , at the top of the water trajectory V2=0V_2=0 and the reference level z1=0z_1=0


Bernoulli's equation


P1ρg+V122g+zi=P2ρg+V222g+z2\frac{P_1}{\rho g}+\frac{V^2_1}{2g}+z_i=\frac{P_2}{\rho g}+\frac{V^2_2}{2g}+z_2


Since


V122g=V222g=0\frac{V^2_1}{2g}=\frac{V^2_2}{2g}=0


the equation reduces to


P1ρg=Patmρg+z2\frac{P_1}{\rho g}=\frac{P_{atm}}{\rho g}+z_2


Solving for z2z_2 and substituting.


z2=P1Patmρg=P1,gaugeρgz_2=\frac{P_1-P{atm}}{\rho g}=\frac{P_1,{gauge}}{\rho g}


400kPa1000kg/m3×9081m/s2(1000N/m21kPa)(1kg.m/s21N)\frac{400kPa}{1000kg/m^3\times9081m/s^2}(\frac{1000N/m^2}{1kPa})(\frac{1kg.m/s^2}{1N})


answer =40.8m40.8m




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