Solution
Given data in question
Specific gravity ="0.85"
density of fluid
("\\rho) =0.85\\times1000=850Kg\/m^3"
atmospheric pressure "(P_{atm}) =96\\times10^3Pa"
Height of fluid in Manometer
"(h) =0.55m"
Therefore Pressure in the tank can be given by
"P=P_{atm}+\\rho gh"
"P=96\\times10^3+850\\times9.81\\times0.55"
"P=96\\times10^3+4.58\\times10^3"
"\\fcolorbox{red}{yellow}{$P=100.58KPa$}"
Therefore absolute pressure on the tank is 100.58KPa .
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