Question #130094

A manometer is used to measure the
pressure in a tank. The fluid used has a
specific gravity of 0.85, and the
manometer column height is 55 cm, as
shown in the Fig. If the local atmospheric
pressure is 96 kPa, determine the
absolute pressure within the tank?

Expert's answer

Solution

Given data in question

Specific gravity =0.850.85

density of fluid

(ρ)=0.85×1000=850Kg/m3\rho) =0.85\times1000=850Kg/m^3

atmospheric pressure (Patm)=96×103Pa(P_{atm}) =96\times10^3Pa


Height of fluid in Manometer

(h)=0.55m(h) =0.55m

Therefore Pressure in the tank can be given by

P=Patm+ρghP=P_{atm}+\rho gh

P=96×103+850×9.81×0.55P=96\times10^3+850\times9.81\times0.55

P=96×103+4.58×103P=96\times10^3+4.58\times10^3


P=100.58KPa\fcolorbox{red}{yellow}{$P=100.58KPa$}


Therefore absolute pressure on the tank is 100.58KPa .


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