Question #130092

A plate having an area of 0.6 m2
is sliding down an inclined plane
at 30° to the horizontal with a velocity of 0.36 m/s. There is a
cushion of fluid 1.8mm thick between the plane and the plate. Find
the viscosity of the fluid if the weight of the plate is 280N?

Expert's answer

F=ηΔvΔxA→η=FΔvΔxA=F=\eta\frac{\Delta v}{\Delta x}A\to \eta=\frac{F}{\frac{\Delta v}{\Delta x}A}=


=mgsin⁡30°ΔvΔxA=280sin⁡30°0.361.8⋅10−3⋅0.6=1.17(Pa⋅s)=\frac{mg\sin30°}{\frac{\Delta v}{\Delta x}A}=\frac{280\sin30°}{\frac{0.36}{1.8\cdot10^{-3}}\cdot0.6}=1.17(Pa\cdot s)








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