Question #129925

If an object of mass 4kg goes round a circle of a radius 0.5m in 3.142, what is the force towards the centre(π=3.142)


1
Expert's answer
2020-08-19T13:55:05-0400

Th force towards the centre is the centripetal force

F=mV2rF=\frac{mV^{2}}{r}

The distance round a circle is the circumference of a circle 2π2\pi

Time taken to go round circle =3.142s=3.142s

Velocity of object

=distance/time=V=2π3.142=distance/time=V =\frac{2\pi}{3.142}


=2×3.1423.142=2ms1=\frac{2\times3.142}{3.142}=2ms^{-1}


F=mV2rF=\frac{mV^{2}}{r}


=4×220.5=\frac{4\times2^{2}}{0.5}


=32N=32N



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Comments

Richard
12.10.21, 23:23

Thnks so much...you are a life saver

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