A child is pulling block of mass M = 5 kg on a rough surface
with a force of F1 = 30 N at an angle of θ = 30° to the
horizontal axis. The friction force F2 = 10 N.
Find out magnitude of resultant force
Draw the resultant force.
Given
Applied force F1=30NF_1=30 NF1=30N
Frictional force F2=10NF_2=10 NF2=10N
The resultant force is
R=(F12+F22+2F1F2cos150o)=((30)2+(10)2+2(30)(10)cos150o)=480NR=\sqrt{(F_1^2+F_2^2+2F_1F_2cos150^o)}=\sqrt{((30)^2+(10)^2+2(30)(10)cos150^o)}=480 NR=(F12+F22+2F1F2cos150o)=((30)2+(10)2+2(30)(10)cos150o)=480N
Diagram: