"v = 0.0625t^2"
The acceleration by definition is "a(t) = \\frac{dv}{dt}= 0.0625 \\cdot 2 \\cdot t= 0.125t"
At the time t=10 s: "a(10) = 0.125 \\cdot 10= 1.25 \\; \\frac{m}{s^2}"
Answer: "a(10) = 1.25 \\; \\frac{m}{s^2}"
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