Question #128859

1. A particle is travelling along a straight path described as = 0.75x . If its position along the x axis is
x= (8t)m, where t is in seconds, determine its speed when t=2s.

Expert's answer

Particle A particle is travelling along a straight path described as y=0.75xy= 0.75x .

And, x=8t    y=0.75×8t=6tx=8t \implies y=0.75\times 8t=6t

So particle path is given by s=(8t) i^+(6t) j^s=(8t) \ \hat{i} +(6t)\ \hat{j}

Velocity of Particle (v)=dsdt=ddt(8t)i^+ddt(6t)j^=8i^+6j^ m/s(v)=\frac{ds}{dt}=\frac{d}{dt} (8t) \hat{i} +\frac{d}{dt} (6t) \hat{j}=8\hat{i}+ 6\hat{j}\ m/s

Or Magnitude will be v=82+62=10 m/s|v| =\sqrt{8^2+6^2}=10 \ m/s


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