Answer to Question #128856 in Mechanics | Relativity for Ariyo Emmanuel

Question #128856
The position of a particle along a straight line is given by s= (1.5t^3 − 13.5t^2+ 22.5t)ft, where t is in seconds. Determine the position of the particle when t = 6 s and the total distance it travels during the 6s time interval.
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Expert's answer
2020-08-27T10:41:04-0400

The position of a particle

s(t)=1.5t313.5t2+22.5s(t)=1.5t^3-13.5t^2+22.5

Hence

s(6)=1.5×6313.5×62+22.5=139.5fts(6)=1.5\times 6^3-13.5\times 6^2+22.5=-139.5\:\rm ft

The total distance that particle travels during the 6s time interval

d=s(6)s(0)=139.522.5=162ftd=|s(6)-s(0)|=|-139.5-22.5|=-162\:\rm ft

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