Answer to Question #128722 in Mechanics | Relativity for Ariyo Emmanuel

Question #128722
(1) A rectangular block of metal of 50 mm x 25 mm cross-section and 125 mm length carries a tensile load of 100 kN along its length, a compressive load of 1.0 MN on its 50 x 125 mm faces and a tensile load of 400 kN on its 25 x 125 mm faces. If E = 208 GN/m² and Poisson’s ratio = 0.3, Find (a) change in volume of bar (b) increase required in 1.0 MN load to produce no change in volume.
1
Expert's answer
2020-08-18T10:09:16-0400

(a)


σx=Fxab=1002550=80(N/mm2)\sigma_x=\frac{F_x}{a\cdot b}=\frac{100}{25\cdot50}=80(N/mm^2)


σy=Fyhb=100012550=160(N/mm2)\sigma_y=\frac{F_y}{h\cdot b}=-\frac{1000}{125\cdot50}=-160(N/mm^2)


σz=Fyha=40012525=128(N/mm2)\sigma_z=\frac{F_y}{h\cdot a}=\frac{400}{125\cdot25}=128(N/mm^2)


V=1252550=156250(mm3)V=125\cdot25\cdot50=156250(mm^3)


dVV=(σxσy+σz)(12u)E=(80160+128)(120.3)208103=\frac{dV}{V}=\frac{(\sigma_x-\sigma_y+\sigma_z)(1-2u)}{E}=\frac{(80-160+128)(1-2\cdot0.3)}{208\cdot10^3}=


=9.23105=9.23\cdot 10^{-5}


ΔV=V9.23105=\Delta V=V\cdot 9.23\cdot 10^{-5}=


=1562509.23105=14.42(mm3)=156250\cdot9.23\cdot 10^{-5}=14.42(mm^3)


(b)


σxσy+σz=0\sigma_x-\sigma_y+\sigma_z=0


σyhb=Fy\sigma_y\cdot h\cdot b=F_y\to


Fy=20812550=1300000(N)=1300(kN)F_y=208\cdot125\cdot50=1300000(N)=1300(kN)







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