Question #128494
7. An 80.0 kg student running at 3.5 m/s grabs onto a rope that it hanging vertically.
a. How much kinetic energy does the student have prior to grabbing the rope?
b. How high will the student swing?
1
Expert's answer
2020-08-10T12:32:19-0400

a. Ek=mv22=803.522=490E_k={{mv^2}\over2}={{80\sdot{3.5^2}}\over2}=490 J

b. Ek=Ep    E_k=E_p\implies mv22=mgh    {{mv^2}\over2}=mgh\implies h=v22g=3.5229.81=0.624h={{v^2}\over2g}={{{3.5^2}}\over2\sdot9.81}=0.624 m = 62.4 cm


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS