As per the given question,
Initial velocity of the rocket ship (u)=0
Final velocity of the rocket ship (v)=28000 km/hour
Final height(h) = 300km
Now, applying newton's 3rd equation of motion,
"v^2= u^2+2ah"
"\\Rightarrow a=\\frac{v^2-u^2}{2h}"
Now, substituting the values,
"a=\\frac{28000^2 -0}{2\\times 300}=\\frac{3920000k}{3} km\/hour^2 =100.82 m\/sec^2"
Hence, the apparent weight of the astronaut
"W= mg+ma =(75\\times 9.8 + 75\\times 100.82 )N"
"\\Rightarrow W = 8296.5 N"
When he reached in the orbit then the gravitational force will be balanced by the centripetal force so the net reaction force on the astronaut will be zero. Hence He will experience weightlessness in the ship.
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