Answer to Question #125875 in Mechanics | Relativity for Y

Question

2. In 30 s, the crankshaft of a truck engine operating at 2400 rpm turns through how many radians?

Answer 1

As far, as the truck engine operating at 2400 rpm performns 2400 revolutions per minute, then it will perform $2400/2 = 1200$ revolutions during 30 s.

One revolution correspondes to $2\pi$ radians. Thus, during 30 s the truck engine turns through:

$N = 1200\cdot 2\pi = 2400\pi \approx 7539.8 \space (radians)$

Answer. 2400pi or 7539.8 radians.