a pully system has a two boxes. box 1 is on a ledge and has a mass of 2.0×10 to the power of 3 kg, box 2 is attached by a rope at a 90° angle blow box one and has a mass of 4.4×10 to the power of 2 kg. There is a man standing on box number two, what is the apparent weight of the man if all surfaces are frictionless?
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Expert's answer
2020-07-10T10:22:46-0400
According to the second Newton's law
"Ma=T"
"mg-T=ma"
"m_1g-N=m_1a"
So, we get
"N=m_1g-m_1\\frac{mg}{M+m}"
Assume that the man has a mass "m_1=60 kg" . Finally
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