Answer to Question #125867 in Mechanics | Relativity for Sammy W-S

Question #125867
a pully system has a two boxes. box 1 is on a ledge and has a mass of 2.0×10 to the power of 3 kg, box 2 is attached by a rope at a 90° angle blow box one and has a mass of 4.4×10 to the power of 2 kg. There is a man standing on box number two, what is the apparent weight of the man if all surfaces are frictionless?
1
Expert's answer
2020-07-10T10:22:46-0400


According to the second Newton's law


Ma=TMa=T

mgT=mamg-T=ma

m1gN=m1am_1g-N=m_1a


So, we get


N=m1gm1mgM+mN=m_1g-m_1\frac{mg}{M+m}


Assume that the man has a mass m1=60kgm_1=60 kg . Finally


P=N=m1gm1mgM+m=609.81604409.812000+440=482NP=N=m_1g-m_1\frac{mg}{M+m}=60\cdot9.81-60\cdot\frac{440\cdot9.81}{2000+440}=482 N






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