Answer to Question #125737 in Mechanics | Relativity for Midhun

Question

Two bodies have a mass of ratio 3 is to 4 the force applied on bigger mass production and acceleration of 12 mass per second what would be the acceleration of other body to the same force acts on it

Answer 1

The ratio of masses is $\dfrac{m_1}{m_2} = \dfrac{3}{4}$. According to the second Newton's law, the force is:

$$F = ma$$

where $a$ is acceleration delivered to the body.

If the force is the same for both bodies, then:

$$m_1a_1 = m_2a_2\\ \dfrac{m_1}{m_2} = \dfrac{a_2}{a_1} = \dfrac{3}{4}$$

From the last equation:

$$a_2 = \dfrac{3}{4}a_1$$

If $a_1 = 12 m/s^2$, then:

$$a_2 = \dfrac{3}{4}12m/s^2 = 9m/s^2$$

Answer. 9 m/s^2.