Question #125498

A support supplies a force 5 kN to a wall as shown below. What is the x component of the moment (in kN-m) produced by this force about an axis in the direction of i+j+k(from the origin)?

Expert's answer

Force is 5 kN


Horizontal Component i=Fx=5cosθi = F_x = 5 cos \theta


Vertical Component j=Fy=5sinθj =F_y = 5 sin \theta


 xx component of the moment (in kN-m)  =M=Fx×d=5cosθ×d(kN−m)= M = F_x \times d = 5 cos \theta \times d (kN-m)

dd is the distance of the force form origin


Force about an axis in the direction of i+j+k=Fx+Fy+Fz=5cosθ+5sinθ+0=5(cosθ+sinθ)i+j+k = F_x + F_y +F_z = 5cos\theta+5sin\theta+0=5(cos\theta+sin\theta)


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