Answer to Question #1244 in Mechanics | Relativity for Jessica

Question

A juggler throws a ball from height of 0.950 m with a vertical velocity of +3.50 m/s and misses it on the way down. What is its velocity when it hits the ground?

Answer 1

According to the equations of the motion:
h = h₀ +v₀t - gt²/2;
v = v₀ - gt.


h₀ = 0.95
v₀ = 3.5 m/s
h = 0

0 = 0.95 +3.5t - 10t²/2
5t² - 3.5t - 0.95 = 0
D = 3.5² + 5*0.95*4 = 31.25
t₁ = (3.5+5.6) / 10 = 0.91
t₂ = -0.21 - out of sense.

v = 3.5 - 0.91*10 = -5.6 m/s
Answer:
The velocity would be equal to 5.6 m/s and its vector is directed downward.