Answer to Question #123984 in Mechanics | Relativity for Abhi

Question

Awheel rotating about a fixed axis at 24 r.p.m. is uniformly accelerated for 70 seconds,
during which time it makes 50 revolution. Find (i) angular velocity at the end of this
interval, and (ii) time required for the speed to reach 150 r.p.m.
(Ans. - 61.4 r.p.m. ;3 min 55.6 s)

Answer 1

Explanations & Calculations

• Equivalent forms of the equations used in linear motion under uniform acceleration are used in rotational motion.

1).

• Apply $\small \theta = \Big(\frac{\omega_{final}+\omega_{initial}}{2} \Big)\small t$ to calculate the angular velocity.

$\qquad\qquad \begin{aligned} \small 50 rev. &= \small \Big(\frac{\omega_{final}+24 \,r.p.m}{2}\Big)\times \Big(\frac{70}{60} min\Big)\\ \small \omega_{final}&= \small \bold{61.71 \,rpm } \end{aligned}$

• Before stepping forward, angular acceleration ($\alpha$ )should be calculated. Apply $\small \omega_{final} = \omega_{initial} +\alpha t$ to calculate it.

$\qquad\qquad \begin{aligned} \small \alpha &= \small \frac{\omega_f -\omega_I}{t}\\ \small &= \small \frac{61.71 -24}{(\frac{70}{60})}\cdots\cdots(1)\\ \end{aligned}$

• And there is no need to calculate it as a final figure since it's not asked to calculate.

2)

• Apply again the above relationship from start to when it makes 150 rpm s.

$\qquad\qquad \begin{aligned} \small \alpha &= \small \frac{150 rpm -24rpm}{t} \cdots\cdots(2) \end{aligned}$

• By (1) = (2), time take to reach 150 rpm s,

$\qquad\qquad \begin{aligned} \small \frac{61.71 -24}{(\frac{70}{60})} &= \small \frac{150 rpm -24rpm}{t} \\ \small t &= \small 3.898min\cdots(3min+0.898min)\\ &= \small 3min +(0.898\times60s)\\ &= \small \bold{3min\,53.9s} \end{aligned}$

$\qquad\qquad \begin{aligned} \end{aligned}$