Question

A friend throws a baseball horizontally. He releases it at a height of 2.0 m and it lands 21 m from his front foot, which is directly below the point at which he released the baseball. (a) How long was it in the air? (b) How fast did he throw

Answer 1

According to the equations of the motion for vertical projecton of the velocity (V_0y = 0):
V = gt;
h₀= gt²/2;

2 = 10t²/2;
a) t = 0.63 s
b) V_0x =s/t = 21/0.63 = 33.33 m/s