Solution.
d=25mm;d=25mm;d=25mm;
F=20000N;F=20000N;F=20000N;
E=70000N/mm2;E=70000N/mm^2;E=70000N/mm2;
σ=FS;\sigma=\dfrac{F}{S};σ=SF;
S=πd24;S=\dfrac{\pi d^2}{4};S=4πd2;
σ=Eϵ ⟹ ϵ=σE;\sigma=E\epsilon\implies\epsilon=\dfrac{\sigma}{E};σ=Eϵ⟹ϵ=Eσ;
S=3.14⋅(25mm)24=490.625mm2;S=3.14\sdot\dfrac{(25mm)^2}{4}=490.625mm^2;S=3.14⋅4(25mm)2=490.625mm2;
σ=20000N490.625mm2=40.76N/mm2;\sigma=\dfrac{20000N}{490.625mm^2}=40.76N/mm^2;σ=490.625mm220000N=40.76N/mm2;
ϵ=40.76N/mm270000N/mm2=0.00058=0.058%;\epsilon=\dfrac{40.76N/mm^2}{70000N/mm^2}=0.00058=0.058\%;ϵ=70000N/mm240.76N/mm2=0.00058=0.058%;
Answer: ϵ=0.058%.\epsilon=0.058\%.ϵ=0.058%.
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