Solution.
"d=25mm;"
"F=20000N;"
"E=70000N\/mm^2;"
"\\sigma=\\dfrac{F}{S};"
"S=\\dfrac{\\pi d^2}{4};"
"\\sigma=E\\epsilon\\implies\\epsilon=\\dfrac{\\sigma}{E};"
"S=3.14\\sdot\\dfrac{(25mm)^2}{4}=490.625mm^2;"
"\\sigma=\\dfrac{20000N}{490.625mm^2}=40.76N\/mm^2;"
"\\epsilon=\\dfrac{40.76N\/mm^2}{70000N\/mm^2}=0.00058=0.058\\%;"
Answer: "\\epsilon=0.058\\%."
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