Question #120972
A fan blade is initially rotating an angular speed of 4.6 rpm. It slows down and eventually comes to rest in a time of 32 seconds after turning through a total of 8.8 revolution. Find a.) The angular speed in rad/s. b.) The average angular velocity ang c.) The average angular acceleration.
1
Expert's answer
2020-06-09T13:20:14-0400

Initial angular velocity is ωo=4.6×2π60=0.48rad/s\omega_o=4.6\times \frac{2\pi}{60}=0.48\:rad/s

Final angular velocity is ωf=0rad/s\omega_f=0\:rad/s

Final time t=tf=32st=t_f=32s and angle traversed is θ=8.8×2π=55.29rad\theta=8.8\times2\pi=55.29 \:rad


(a).As we have not provided at which time we need to find the angular speed, thus

we assume time t is arbitrary, hence

ω=ωo+(α)t    ω=ωoαtrad/s\omega=\omega_o+(-\alpha) t\implies \omega=\omega_o-\alpha t\:rad/s

As angular acceleration is decreasing.


(b). Since, average angular velocity is given by

ωav=ΔθΔt\omega_{av}=\frac{\Delta \theta}{\Delta t}

Thus, on plugin the value we get,

ωav=55.290320=1.72rad/s\omega_{av}=\frac{55.29-0}{32-0}=1.72 \: rad/s

(c). Since,

αav=ΔωΔt=ωfωotfto\alpha_{av}=\frac{\Delta \omega}{\Delta t}=\frac{\omega_f-\omega_o}{t_f-t_o}

Hence, on plugin the value we get

αav=00.48320=0.015rad/s2\alpha_{av}=\frac{0-0.48}{32-0}=-0.015 \:rad/s^2


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