Initial angular velocity is ωo=4.6×602π=0.48rad/s
Final angular velocity is ωf=0rad/s
Final time t=tf=32s and angle traversed is θ=8.8×2π=55.29rad
(a).As we have not provided at which time we need to find the angular speed, thus
we assume time t is arbitrary, hence
ω=ωo+(−α)t⟹ω=ωo−αtrad/s As angular acceleration is decreasing.
(b). Since, average angular velocity is given by
ωav=ΔtΔθ Thus, on plugin the value we get,
ωav=32−055.29−0=1.72rad/s
(c). Since,
αav=ΔtΔω=tf−toωf−ωo Hence, on plugin the value we get
αav=32−00−0.48=−0.015rad/s2
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