Answer to Question #120170 in Mechanics | Relativity for pro

Question #120170
A train is travelling at a speed of 90 km h −1 . Brakes are applied so as to produce a
uniform acceleration of −0.5 m s −2 . Find how far the train will go before it is
brought to rest.
1
Expert's answer
2020-06-04T10:04:44-0400

The initial speed of train is v0=90km/h=25m/sv_0 = 90km/h = 25 m/s and the acceleration is 0.5m/s2-0.5m/s^2. According to the kinematic equation:


v0=atv_0 = -at

where tt is the time required to stop the train. Thus:


t=v0a=250.5=50st = -\dfrac{v_0}{a} = -\dfrac{25}{-0.5} = 50s

The distance, traveled by train by this time is:


d=v0t+at22=25500.55022=625md = v_0t + \dfrac{at^2}{2} = 25\cdot 50 - \dfrac{0.5\cdot 50^2}{2} = 625 m

Answer. d = 625 m.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment