Question #118776
Two batteries P and Q each of Emf 8 V and 3 V have internal resistance of 2 Ω and 4 Ω respectively.
Calculate the values of the current through the circuit
1
Expert's answer
2020-05-29T09:58:34-0400

Explanations & Calculations




  • Two batteries (P & Q) could be connected in either way as show above.
  • For the ease of understanding, it's allowed to represent the internal resistance of the battery, just outside it.
  • And apply Kirchoff's voltage law in the shown direction.


1) To find i1i_1 ,

8Vi1×2Ωi1×4Ω3V=0i1×6Ω=5Vi1=0.833A\qquad\qquad \begin{aligned} \small 8V-i_1\times 2\Omega-i_1\times 4\Omega-3V &= \small 0\\ \small i_1 \times 6\Omega &= \small 5V\\ \small i_1 &= \small \bold{0.833A} \end{aligned}

  • 3V battery is being charged in this arrangement.


2) To find i2i_2


8Vi2×2Ωi2×4Ω+3V=0i2×6Ω=11Vi2=1.833A\qquad\qquad \begin{aligned} \small 8V-i_2\times2\Omega -i_2 \times 4\Omega +3V &= \small 0\\ \small i_2 \times 6 \Omega &= \small 11V\\ \small i_2 &= \small \bold{1.833 A} \end{aligned}



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