According to the https://en.wikipedia.org/wiki/Geosynchronous_orbit#Period, the altitude of the satellite is given by:
where "G = 6.67\\cdot 10^{-11} m^3 kg^{-1} s^{-2}" is the gravitational constant, "M_{Earth} = 5.98\\cdot 10^{24} kg" is the mass of Earth, "T" is the period of satellite revolution. On the geosynchronous orbit "T = 24 h = 86400 s".
Thus:
The acceleration on this height is:
where "R = 6.38\\cdot10^6" is the radius of the Earth
Assuming the circular orbit, the speed will be:
Answer. v = 2.87 km/s, h = 42.2 km.
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